how many are there in the competition

Given:

Ratio of Boys lớn Girls who participate in Dancing = 4 : 3

Bạn đang xem: how many are there in the competition

Ratio of Boys lớn Girls who participate in Singing = 8 : 13

Ratio of Boy lớn Girl who participates in both the events of Singing and Dancing = 2 : 1

Ratio of Boys lớn Girls who participate only in the Singing sự kiện = 1 : 2

participation of boys in the Dancing sự kiện alone is 10 more phàn nàn the Girls participation in Dancing alone

Boys who participate in both Dancing and Singing is 20% of the Boys who participate in Dancing events alone

Concept:

F1 Vaibhav.S 16-12-20 Savita D1

Total participant in Dance = participate only in Dance + participate in both Dancing and Singing

Total participant in Singing = participate only in Singing + participate in both Dancing and Singing

Total participant in competition = participate only in Dance + participate in both Dancing and Singing + participate only in Singing

Calculation:

Let number of Girl participate only in khiêu vũ = x

So, Number of Boys participate only in khiêu vũ = x + 10

Number of Boys participate in both Dancing and Singing = (20/100) × (x + 10)

⇒ (x + 10)/5

Number of Girls participate in both Dancing and Singing = (1/2) × {(x + 10)/5}

⇒ (x + 10)/10

Number of Boys participate in dance/Number of girls participate in dance = 4/3

4/3 = {(x + 10) + (x + 10)/5}/{x + (x + 10)/10}

⇒ 2/3 = (6x + 60)/(11x + 10)

⇒ 18x + 180 = 22x + 20

⇒ 4x = 160

⇒ x = 40

Number of Girl participate only in khiêu vũ = 40

Number of Boys participate only in khiêu vũ = 40 + 10

⇒ 50

Number of Boys participate in both Dancing and Singing = (40 + 10)/5

⇒ 10

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Number of Girls participate in both Dancing and Singing = (40 + 10)/10

⇒ 5

F1 Vaibhav.S 16-12-20 Savita D2

Number of Boys participate in dance = 50 + 10

⇒ 60

Number of girls participate in dance = 40 + 5

⇒ 45

F1 Vaibhav.S 16-12-20 Savita D3

Number of Boys in singing/Number of Girls in singing = 8/13

8/13 = (10 + y)/(5 + 2y)

⇒ 40 + 16y = 130 + 13y

⇒ 3y = 90

⇒ nó = 30

Number of Boys in singing only = 30

Number of Girls in singing only = 2 × 30

⇒ 60

F1 Vaibhav.S 16-12-20 Savita D4

F1 Vaibhav.S 16-12-20 Savita D2

Number of Boys in singing = 30 + 10

⇒ 40

Number of Girls in singing = 60 + 5

⇒ 65

Total participant in competition = (50 + 40) +(10 + 5) + (30 + 60)

⇒ 90 + 15 + 90

⇒ 195

∴ Total 195 participants were there in the competition.

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